Answer:
d ≈ 1732 ft
Step-by-step explanation:
Angle of elevation = Angle of depression
Following this truth,
m∠PAQ (Angle of depression) = m∠APB (Angle of elevation) = 30°
By applying tangent rule in the given triangle ABP,
tan(30°) =
d = 1000√3
d = 1732.05
d ≈ 1732 ft
(A.)test statistic for this test using Ha: p8くPN is Z = -2.164 (B.) p-value (3 decimal places) is 0.015. (C.) Based on this p-value, which of the following would you expect for a 95% is negative. (D.) the correct conclusion is The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.
A.)
According to given data find the test statistic for this test using Ha:
p1 = 0.581
p2 = 0.832
standard error = SE = 0.116
<h3>Test statistics :-</h3>Z =
Z = = -2.164
Z = -2.164
B.)
According to given Determine the p-value (3 decimal places).
<h3>p - value</h3>it is left tailed test.
p - value for left tailed test is,
p - value = P(Z < test statistics )
p - value = P(Z < -2.164)
P - value = 0.015
C.)
Based on this p-value, which of the following would you expect for a 95%
confidence level = 95% = 0.95
significance level = α = 0.05
P -value is less than 0.05
so, reject null hypothesis at α = 0.05
That is <
so, based on P - value , All values in the 95% confidence interval
PB - PNY is negative.
D.)
According to given data What is the correct conclusion?
Reject null hypothesis at α = 0.05
so, <
Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.
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Answer:
Velocity of the plane relative to the ground
= [(-145.98î) + (15j)] knots
Magnitude = groundspeed = 146.75 knots
Direction = -5.9°
Step-by-step explanation:
This is a relative velocity question.
Let the velocity of the airplane relative to the wind be V(aw)
Velocity of the airplane relative to the ground = Va
The velocity of the wind relative to the ground = Vw
The relative velocity theory enables us o relate these as thus,
V(aw) = Va - Vw
Va = V(aw) + Vw
V(aw) = (-120î) knots (120 west)
For Vw, the wind is said to be blowing from 120°, reading this on a three figure bearing as angle from the north,
This gives the real direction of the wind to be 150° from the positive x-axis as shown in the attached image.
Vw = (30cos 150°)î + (30sin 150°)j
Vw = (-25.98î + 15j) knots
Va = V(aw) + Vw = (-120î) + (-25.98î + 15j)
Va = (-145.98î) + (15j)
Magnitude of Va = √[(-145.98)² + (15)²] = 146.75 knots
Direction = tan⁻¹ (-15/145.98) = -5.9°
Hope this Helps!!!
