The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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A) 0.955 and 199/200
B) 1.40 or 1.4 and 1 2/5
C) 0.90 or 0.9 and 9/10
Answer:
340.2
Step-by-step explanation:
18.0 x 18.9 = 340.2
Answer:
0.1
Step-by-step explanation:
73/844=0.08649=0.1(After rounding)
The ordered pair (7, 19) is only a solution to the first equation, 14-19= -5. the ordered pair is not a solution to the second equation 7 + 57 does not equal 22.
