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2 years ago

Which of the following is not a way to determine if a relation is a function?

Mathematics

1 answer:

Dima020 [189]2 years ago

8 0

D. Determine if the relations’ graph forms a line.

Step-by-step explanation:

A function is a relation if the input values lead to only one output value.The input values, normally x values make up the domain, where as the output values form the domain.A function is a relation where the input values are associated with a single output.The vertical test is used to determine if a curve is a function.The line graph should only hit a single point on the curve.

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Relations and Functions :brainly.com/question/3296514

Keywords; relation, a function, vertical line test, output, input, maps

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Add.

Phoenix [80]

The answers is 11x+2 I’m pretty sure. I can’t tell if your x3 was an exponent or multiplying.

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3 years ago

If Shane’s average number of jumps completed is greater than one-half, then the

Norma-Jean [14]

Ok so, it all depends if Shane is likely to jump win over all of the other seventh graders then the eighth graders should earn the 50 points...

But if the roles are reversed the the Seventh graders should earn the 50 points.

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2 years ago

a banner is made of a sqiare and a semocircle. the square has side lengths of 26 inches. one side of the square is also the diam

tamaranim1 [39]

ARea = area of square + area of semicircle

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2 years ago

Read 2 more answers

I have one more question I can figure out how to get the answer via the calculator but I'm not sure how I got there

valentinak56 [21]

Answer:

43.6 * 2.94 = 436/10 * 294/100 = (436 * 294)/1000 = 128184/1000 = 128.184

4 0

3 years ago

What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1

andrew11 [14]

Step 1. Simplify $\frac{1}{5} (x+5)$ to $\frac{x+5}{5}$

$\frac{x+5}{5} = \frac{1}{4} (x-3)+1$

Step 2. Simplify $\frac{x+5}{5}$ to $1+ \frac{x}{5}$

$1+ \frac{x}{5} = \frac{1}{4} (x-3)+1$

Step 3. Simplify $\frac{1}{4} (x-3)$ to $\frac{x-3}{4}$

$1+ \frac{x}{5} = \frac{x-3}{4} +1$

Step 4. Cancel $1$ on both sides

$\frac{x}{5} = \frac{x-3}{4}$

Step 5. Multiply both sides by $20$ (the LCM of $5,4$ )

$4x=5(x-3)$

Step 6. Expand

$4x=5x-15$

Step 7. Subtract $5x$ from both sides

$4x-5x=-15$

Step 8. Simplify $4x-5x$ to $-x$

$-x=-15$

Step 9. Multiply both sides by $-1$

$x=15$

Done! :) Hope this helps! :)

3 0

3 years ago