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Reptile [31]
3 years ago
9

Solve for x 5x - 1 =26

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

x=5.4

Step-by-step explanation:

you get rid of the -1 by adding 1 and you have to do it to both sides so you would have 5x=27 and then just ÷ so 27÷5= 5.4 so x=5.4

Ksivusya [100]3 years ago
4 0

Answer:

x=5.4

Step-by-step explanation:

5x-1=26            Isolate the variable

+1      +1

5x=27               Divide by 5.

x=5.4

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Answer:

719

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,
m_a_m_a [10]

The Cartesian coordinate plane, specify locations by a pair of coordinates that indicate the magnitude in perpendicular, x, and y directions

The correct responses are;

  • Part A: The starting point is in the second quadrant and the finishing point is in the fourth quadrant.
  • Part B: The starting point and the check point are on different quadrant. Both points are on the same horizontal line.

Reasons:

The location of the start point of the race = (-5.3, 1)

Location of the finishing point = (1, -5.3)

Part A: The signs of the <em>x</em> and <em>y</em>-values in the quadrants are;

  • \begin{tabular}{|cc|c|}Quad II, x -ve, y +ve&&Quad I, x, and y are +ve\\&&\\Quad III, x -ve, y -ve&&Quad IV, x +ve, y -ve\end{array}\right]

The coordinates of the starting point is (-5.3, 1), therefore, given that the x-

coordinate is negative and the y-coordinate is positive, the quadrant of the

starting point is quadrant II (the second quadrant).

  • <u>The quadrant of the starting point is the second quadrant</u>.

The coordinates of the finishing point is (1, -5.3), the x-value is positive and

the y-value is negative, which indicates that the quadrant of the finishing

point is quadrant IV (the fourth quadrant).

  • <u>The quadrant of the finishing point is the fourth quadrant</u>.

Part B: The location of the checkpoint is; (5.3, 1)

The difference is that the x-value of the checkpoint is positive while the x-value of the starting point is negative, and they are therefore on different quadrants.

The similarity is that, the magnitude of the <em>x</em>, and <em>y</em> values of the coordinates of the check point and the starting point are the same. Therefore, the checkpoint and the starting point are on <u>the same horizontal line</u>.

Learn more about the Cartesian coordinate plane here:

brainly.com/question/17877300

brainly.com/question/16177011

8 0
3 years ago
Find the circumference and area of a circle with the diameter AB,<br> A(-8,4) and B(4,-1)
bezimeni [28]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-8}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[4-(-8)]^2+[-1-4]^2}\implies AB=\sqrt{(4+8)^2+(-1-4)^2} \\\\\\ AB=\sqrt{144+25}\implies AB=\sqrt{169}\implies \stackrel{\textit{diameter}}{AB=13}~\hfill \boxed{\stackrel{\textit{radius}}{6.5}} \\\\[-0.35em] ~\dotfill

\bf \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi (6.5)\implies C=13\pi \implies C\approx 40.84 \\\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (6.5)^2\implies A=42.25\pi \implies A\approx 132.73

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What is the value of x?
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Answer:

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55

Hope this helps

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3 years ago
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It’s C cash advances after the introductory period.
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