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Leni [432]
3 years ago
6

20+(5 + 7) = x - 14 I need help take your time

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0

Answer: x = 46

Step-by-step explanation: 20 + (5 + 7) = x - 14, 20 + (12) = x - 14

lesya692 [45]3 years ago
4 0

Answer:

x=46

Step-by-step explanation:

20 + (5+7)=x-14

20+12=x-14

32=x-14

Take x-14 on the other side of the 'equal to' sign and 32 on the other side so that the variable remains on the right side

x-14=32\\

x=32+14

x=46

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If R is the set of all integers, choose the set S that will make the following statement false.
olga55 [171]

Answer: 1 S = {−2, −1, 0, 1, 2}

Step-by-step explanation:

Integers are whole numbers that could be positive or negative .

This means that

R = { ... -3 ,-2 , -1 , 0 , 1 , 2 , 3 , 4 , ...}

S ⊆ R means that all elements of S is also an element in R , therefore :

S = { -2, -1 ,0, 1 , 2 ...}

5 0
3 years ago
Simplify the expression(a4−6a2b2+ b4)−(−2a4+5a2b2+ 3b4) and hence, find its value for a = 2and b = −1.
ELEN [110]

Answer:

(a) 3a^4 - 11a^2b^2 -2b^4

(b) 3a^4 - 11a^2b^2 -2b^4= 2

Step-by-step explanation:

Given

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Solving (a): Simplify

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Open brackets

a^4 - 6a^2b^2+ b^4 +2a^4-5a^2b^2- 3b^4

Collect Like Terms

a^4 +2a^4- 6a^2b^2-5a^2b^2+ b^4 - 3b^4

Simplify Like Terms

3a^4 - 11a^2b^2 -2b^4

Solving (b): Simplify when a = 2 and b = -1

3a^4 - 11a^2b^2 -2b^4

3*(2)^4 - 11*(2^2)*(-1)^2 -2*(-1)^4

3 * 16 - 11 * 4 * 1 - 2 * 1

48 - 44 - 2

= 2

Hence:

3a^4 - 11a^2b^2 -2b^4= 2

4 0
3 years ago
.......................
Anna [14]

Answer:

Mean: 49

Median: 48

Step-by-step explanation:

The mean is the total of all the values by adding them all together, then divided by the number of values.

The median is the middle number in the order of lowest to highest.

5 0
4 years ago
Read 2 more answers
Help me plez i will mark brainlist
inysia [295]

Answer:

The answer is 6 1/3 divided by 2 which is 3 1/6

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
For each of the following pairs of signed integers (2’s complement), subtract the second from the first. Show the decimal equiva
Dmitry_Shevchenko [17]

Answer:

The answers are

a)111010 - 001111 = 101011 = 43

b) 000100 - 011000 = 111111111 (overflow) = -20

c) 010001 - 011010 = 11111111 (overflow) = -9

d) 010000 - 100100 = 1111111 (overflow) = -20

Step-by-step explanation:

a)111010 = 1×2⁵+1×2⁴+1×2³+0×2²+1×2¹+0×2⁰ = 32+16+8+0+2+0= 58

001111 = 0×2⁵+0×2⁴+1×2³+1×2²+1×2¹+1×2⁰ = 8+4+2+1=15

111010 - 001111 = 101011 = 43

b) 000100 = 0×2⁵+0×2⁴+0×2³+1×2²+0×2¹+0×2⁰ = 4

011000 = 0×2⁵+1×2⁴+1×2³+0×2²+0×2¹+0×2⁰  = 24

000100 - 011000 = 1111111111 (overflow), 4 - 24 =-20

c)  010001 = 1×2⁴+1×2⁰ = 17

011010 = 1×2⁴+1×2³+1×2¹ = 26

010001 - 011010 = 11111111 (overflow) 17-26=-9

d) 010000 = 1×2⁴ = 16

100100 = 1×2⁵+1×2² = 36

010000 - 100100 = 1111111 (overflow) 16-36=-20

3 0
3 years ago
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