Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt = 
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) =
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 
9 is the correct answer. 4*2=8 loops are executed, moving the count from 1 to 9.
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In order to grant India access to a list of her friends, you should use a query by selecting name from person and use the inner join relationship on person.
<h3>What is query?</h3>
A query refers to a computational request for data that are saved in a database table, from existing queries, or even from a combination of both a database table and existing queries.
In this scenario, you can grant India access to be able to see a list of her friends with a structured query language (SQL) by selecting name from person and use the inner join relationship on person.
Read more on query here: brainly.com/question/25266787
