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Elis [28]
3 years ago
8

Which of the following is a valid variable name? a. salesTax b. input-string c. 25Percent d. double

Computers and Technology
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

The correct answer of the given question is option(A) i.e salesTax

Explanation:

Variable are the storage area which value varies during the execution of aprogram .

some of the rules of variable are

1 Variable always start with alphabet.

2 We cannot give variable name any reserve keyword.

3 Variable cannot start with digit.

4 We cannot use special symbol like -,$ to declare any variable

In option (b ) input-string ,it is invalid variable because it uses special symbol "-"  to declared the variable.

In option (c) 25Percent , it is invalid variable because it violate the rule of  variable and start with digit.variable cannot start with digit

In option( d )double, it is invalid variable because it violate the rule of  variable because double is keyword and variable never be a keyword.

So option(A) is correct it follow the rule of variable.

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Write a bool function isPalindrome that takes one string parameter and returns true if that string is a palindrome and false oth
kkurt [141]

Answer:

Here is the bool function isPalindrome:

bool isPalindrome(string s)

{  bool palindrome;      

 int j;

 int len = s.length();

 for (int i =0, j= len-1; i < len/2; i++, j--)  

   if (s[i] == s[j])

     palindrome = true;  

   else

     palindrome = false;

 return palindrome; }

Explanation:

The bool function isPalindrome takes a string as parameter and returns true if the string is a palindrome or false if the string is not palindrome. The string variable s holds the string value. In function isPalindrome, there is a bool type variable palindrome. bool is a data type which is used to hold values true or false which is then stored in the palindrome variable.

Next it is being found that how many characters are there in the input string using length() function which returns the length of the string. The length of the string is stored in int type variable len.

Next the for loop starts which has two variables i and j where i starts at 0 position of the input string and j starts at the last position of the string. These two variables move or traverse along the string this way. i variable stops when half the length of the input string is reached. At the end of every iteration i moves forward by the increment of its value to 1 and j moves backwards by the decrement  of its value to 1.

Every the body of  the loop executes, there is an if condition in the body of the loop which checks if the string is a palindrome. This is checked by matching the character at position/index i with the character at position j of the string. This will continue character by character until the i reached half the length of the input string and if every character in i was matched to every character in j then palindrome = true; statement is executed which returns true as the string is a palindrome otherwise palindrome = false; is returned as the string is not a palindrome.

For taking input string from the user and to check if the function isPalindrome() works correctly a main() function is written which takes input string from the user and reads in variable str calls isPalindrome() function. If the string is palindrome then the cout statement in main() function prints the message: String is a palindrome and if the input string is not a palindrome the the following message is displayed in the output screen: String is not a palindrome

int main()

{

string str;

cout<<"Enter a string: ";

cin>>str;

if(isPalindrome(str))

cout<<"String is a palindrome";

else

cout<<"String is not a palindrome";

}

The screenshot of the program along with the output is attached.

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Hence, we can see that based on the fact that several users on the second floor of your company's building are reporting that the network is down and go to the second floor to investigate and find that you are able to access the network, the troubleshooting step that you should take next is to Question User.

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