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Answer:
85.99% of airline passengers incur this fee.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean 46 pounds and standard deviation 3.7 pounds.
This means that
Most airlines charge a fee for baggage that weigh in excess of 50 pounds. Determine what percent of airline passengers incur this fee.
As a proportion, this is 1 subtracted by the pvalue of Z when X = 50. So
has a pvalue of 0.8599
0.8599*100% = 85.99%
85.99% of airline passengers incur this fee.
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