Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
Answer:
0.6154 = 61.54% probability that the student is an undergraduate
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Foreign
Event B: Undergraduate.
There are four times as many undergraduates as graduate students
So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.
Probability the student is foreign:
10% of 80%
25% of 20%. So

Probability that a student is foreign and undergraduate:
10% of 80%. So

What is the probability that the student is an undergraduate?

0.6154 = 61.54% probability that the student is an undergraduate
Answer:
Oh okayy
Step-by-step explanation:
Answer:
Maximum walking speed of camel is 31.749V feet per second
Step-by-step explanation:
Walking speed of an animal is given by :
Speed = 5.7VI (in feet per second) where l is the animal's leg length.
For a camel, leg length is 5.7feet.
So maximum walking speed of camel will be:
Speed of camel = 5.7V * 5.7 = 5.7² V feet per second
Speed of camel = 31.749V feet per second
hence, maximum walking speed of camel is 31.749V feet per second
Answer:
Your answer is 2 1/2.
Step-by-step explanation:
Divide 9 pounds of sand into 4 buckets, or 9÷4. This equals 2.5 pounds of sand in each bucket.