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Gala2k [10]
3 years ago
12

Provides a unique set of guidelines that can be applied to any triangle. The guidelines demonstrate a clear understanding of app

lying the laws of sines and cosines.
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

we can have a triangle  and we know that there are two angles. 

30º and a 45º + 105 =180º angle. applying the sides. 

therefore if we have the whole triangle completed we have a constant triangle. 


so it tell us we can you’se SOH CAH TOA 

we can varrify what kind of triangle we are using. 


for example if we were to use  Sin I would do 


Sin 30/ 2 = sin of 105º/ A = sin=45º/ B


if you would want to solve for  sin 30/2 and sin 105, then we solve. 

 

or Sin 30/2  and Sin 105 as well. 


with your calculator use sin= 30=.5  and use sin 105º a divide by 1.5 on both sides    1.5= A /sin 105º * 1.5   answer would be 3.86.  a is = to 3.86 (Not the answer)


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3 years ago
F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function
Neporo4naja [7]

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Step-by-step explanation:

Given the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

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f\left(x\right)=\:5x^2\:-\:4x\:+\:9

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6 0
3 years ago
What is the area of the shaded portion of the circle?
SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

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If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from A_1.

The area of the triangle is given by

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Thus the area of the shaded portion of the circle is

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3 0
3 years ago
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