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2 years ago

12

Provides a unique set of guidelines that can be applied to any triangle. The guidelines demonstrate a clear understanding of app

lying the laws of sines and cosines.

1 answer:

Oksi-84 [34.3K]2 years ago

5 0

we can have a triangle and we know that there are two angles.

30º and a 45º + 105 =180º angle. applying the sides.

therefore if we have the whole triangle completed we have a constant triangle.

so it tell us we can you’se SOH CAH TOA

we can varrify what kind of triangle we are using.

for example if we were to use Sin I would do

Sin 30/ 2 = sin of 105º/ A = sin=45º/ B

if you would want to solve for sin 30/2 and sin 105, then we solve.

or Sin 30/2 and Sin 105 as well.

with your calculator use sin= 30=.5 and use sin 105º a divide by 1.5 on both sides 1.5= A /sin 105º * 1.5 answer would be 3.86. a is = to 3.86 (Not the answer)

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Please solve<br>I really need help

Llana [10]

9514 1404 393

Answer:

x = 12

Step-by-step explanation:

The similarity statement tells you corresponding sides have the same ratio.

AB/BC = FE/EC

x/10 = 6/5

x = 10(6/5)

x = 12

7 0

2 years ago

What is the area of a circle whose equation is (x-3)² + (y + 1) ² =81?

kupik [55]

Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle:

$\frac{(x-x_{1})^2}{r^2}+ \frac{(y-y_{1})_^2}{r^2}=1$

Where $(x_{1}, y_{1})$ is the centre of the circle. In this case, we don't need to know the centre. Just the radius.

Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.

$\frac{(x-3)^2}{81}+ \frac{(y+1)^2}{81}=1$

Great! We now know the radius of the circle. It is $\sqrt{81}$ because it is the bottom fraction. Now we know that the radius is 9.

So now lets input this into the area of circle formula:

$A=πr^2$

Now we insert our radius.

$A=9^2π$

$=A=81π$

You can convert that into a decimal if you wish.

Hope this helped!

~Cam943, Moderator

4 0

3 years ago

HURRY!! NO SPAM!!!!!!!!!!!!!!!!!!

Zielflug [23.3K]

2moles of NaCl produced by 2 moles of NaClO_3
Let required moles be x .

$\\ \bull\sf\longmapsto 2:2=3:x$

$\\ \bull\sf\longmapsto \dfrac{2}{2}=\dfrac{3}{x}$

$\\ \bull\sf\longmapsto \dfrac{3}{x}=1$

$\\ \bull\sf\longmapsto x=3mol$

8 0

2 years ago

Read 2 more answers

What is the volume of the square-based pyramid?

grandymaker [24]

Answer:

Volume of square-based pyramid = 96 in³

Step-by-step explanation:

Given:

Base side of square = 6 inch

Height of pyramid = 8 inch

Find:

Volume of square-based pyramid

Computation:

Area of square base = Side x Side

Area of square base = 6 x 6

Area of square base = 36 in²

Volume of square-based pyramid = (1/3)(A)(h)

Volume of square-based pyramid = (1/3)(36)(8)

Volume of square-based pyramid = (1/3)(36)(8)

Volume of square-based pyramid = (12)(8)

Volume of square-based pyramid = 96 in³

6 0

2 years ago

Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p

Juli2301 [7.4K]

I'm reading this as

$\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy$

with $\nabla f=(2xe^{-y},2y-x^2e^{-y})$ .

The value of the integral will be independent of the path if we can find a function $f(x,y)$ that satisfies the gradient equation above.

You have

$\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}$

Integrate $\dfrac{\partial f}{\partial x}$ with respect to $x$ . You get

$\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx$
$f=x^2e^{-y}+g(y)$

Differentiate with respect to $y$ . You get

$\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]$
$2y-x^2e^{-y}=-x^2e^{-y}+g'(y)$
$2y=g'(y)$

Integrate both sides with respect to $y$ to arrive at

$\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy$
$y^2=g(y)+C$
$g(y)=y^2+C$

So you have

$f(x,y)=x^2e^{-y}+y^2+C$

The gradient is continuous for all $x,y$ , so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

$\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e$

8 0

3 years ago