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Hello!
Answer:
1. 
*The answer must have A NEGATIVE SIGN ONLY!*
2. 
*The answer must have A POSITIVE SIGN ONLY!*
3. 
*The answer must have a NEGATIVE SIGN ONLY!*
Step-by-step explanation:
1. 9w=-54
First, you divide by 9 both sides of an equation.
9w/9=-54/9
Simplify.
-54/9=-6
<u><em>W=-6 is the final answer.</em></u>
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2. b-12=3
First you add by 12 both sides of an equation.
b-12+12=3+12
Add by the numbers from left/right.
3+12=15
<u><em>b=15 is the final answer.</em></u>
__________________________________________
3. n/4=-11
First you multiply by 4 both sides of an equation.
4n/4=4(-11)
Multiply by the numbers from left/right.
4*-11=-44
<u><em>n=-44 is the final answer.</em></u>
_____________________________
Hope this helps you!
Have a great day! :)
:D
-Charlie
Thanks!
Create circle B with radius AB
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.