If the width of the garden is w, then the maximum area available is a square, giving you w² as the dimensions. So:
w²=-w²+28w
2w²=28w
w=14
The perimeter is 14 x 4, or 56 feet
How many seed packets??? No idea
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Answer:
The length of the rectangle is 18 cm
The width of the rectangle is 6 cm
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the width of the rectangle
we know that
The perimeter of the rectangle is

we have

so
------> equation A
------> equation B
Substitute equation B in equation A and solve for y
48=2(2y+6+y)
48=2(3y+6)
48=6y+12
6y=48-12
y=36/6=6 cm
Find the value of x
x=2(6)+6=18 cm
The area of the rectangle is
A=xy
A=18*6
A=108 cm^2
Answer:
Imagine that the number that we are looking for is x
We know that:
x/5 - 78 = 9
x/5 = 9 + 78
x/5 = 87
x = 87 . 5 = 435
So the number we need is 435
The answer is definitely 60%
The simplified expression is 17z