Question

A cash register contains only five dollar and ten dollar bills. It contains twice as many five's as ten's and the total amount of money in the cash register is 620 dollars. How many ten's are in the cash register?

Answer 1

Answer:

31

Step-by-step explanation:

Let number of ten dollar bills be x .

So, number of five dollar bills = 2 x

Total amount of money in the cash register = 620 dollars

Amount of money in total cash as a result of  five dollar bills = 2 x × 5 = 10 x  dollars

Amount of money in total cash as a result of  ten dollar bills =  x × 10 = 10 x dollars

According to question ,

Total amount of money in the cash register = Amount of money in total cash as a result of  five dollar bills +  Amount of money in total cash as a result of  ten dollar bills

⇒ 620 = 10 x + 10 x

⇒ 620 = 20 x

⇒ x = $\frac{620}{20}$ = 31

So, number of ten dollar bills = 31