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Vladimir [108]
3 years ago
13

Divide 6/13 by 6/12 . A. 12/13 B. 1/12 C. 9/16 D. 13/12

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0
When doing a problem like this you want to multiply the fraction by the reciprocal. therefore,
6/13 * 12/6 = 72/78


72/78 simplifies to 12/13


12/13 is your answer.
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victus00 [196]
You can just pick any 5 digit decimal and multiply it with any 4 digit decimal to check.

You will see that it has 9 digits after the decimal.
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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Chuge%5Csf%5Cunderline%7BQuestion%7D" id="TexFormula1" title="\huge\sf\underline{Question}"
vekshin1

{\qquad\quad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} }  = 34

[ add 2 on both sides ]

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} } + 2  = 34 + 2

[ form identity : a² + b² + 2ab ]

\qquad \sf  \dashrightarrow \:  {(x)}^{2}  +  { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2}  + 2 \sdot(x)  \sdot  \bigg(\cfrac{1}{x} \bigg)  = 36

[ a² + b² + 2ab = (a + b)² ]

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{2}  = 36

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{}  =  \sqrt{ 36}

\qquad \sf  \dashrightarrow \: x  +  \cfrac{1}{x}    =   \pm 6

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

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2 years ago
Please help me there is a pic thankyou ​
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Answer:

2

Step-by-step explanation:

y^m x y^n = y^m+n

so y^-4 x y⁶ = y^-4+6

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NOTE: ^ means to the power of

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3 years ago
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vladimir1956 [14]

Answer:

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