The answer would be -20 because you add and subtract your numbers to get 20
Answer:
The point is at about (4.5, 100).
Step-by-step explanation:
Minka's line is p = 22t, which has a y-intercept of 0.
Kenji's line is p = 50 + 11t, which has a y-intercept of 50.
Find the line with y-intercept at 0 and the line with y-intercept at 50. Follow the two lines until they intersect. The point of intersection is about (4.5, 100).
You can find this point by setting the two equations equal to each other:
22t = 50 + 11t
Subtract 11t from both sides.
11t = 50
t = 50/11 ≈ 4.545
Then you can find the p value for this point by plugging t = 4.545 into either equation.
p = 22(4.545) = 99.99
p = 50 + 11(4.545) = 99.995
On the graph the point is about (4.5, 100).
Answer:
2.8
Step-by-step explanation:
ur welcome i hope this helps
Answer:
Kayla is correct The center is a fixed point in the middle of the sphere
Step-by-step explanation:
In mathematics we have certain habit of rules for notation of points, coordinates, segments, angles and so on.
Usually we denote points, by letters even more we denote with the first letter of the object we are denoting
Occasionally, we also denote segments as radius in a circle and in a sphere, with letters, that is r stands for radius, h stands for height, in most cases we denote point for capital letters ( in a segment)
When we denote radius, with small letter it should be placed at the center or over the segment we are traying to denote.
For points we only need to place the letter close to the to the point we want to denote.
Therefore Kayla is correct when says that c stand for " the center of the sphere"
The constant of <u>p</u><u>r</u><u>o</u><u>p</u><u>o</u><u>r</u><u>t</u><u>i</u><u>o</u><u>n</u> is the value that relates two variables that are directly proportional or inversely proportional.
- <em>O</em><em>p</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>B</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em>!</em><em>!</em><em>~</em>