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notsponge [240]
3 years ago
13

Find the coordinates of P ' if D o, 2.4 (x,y) is applied to the triangle below

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

The coordinates of P' are (4.8,-4.8).

Step-by-step explanation:

The rule of dilation D_{o,2.4}(x,y) represent the dilation with scale factor 2.4 and center at origin.

If the scale factor of the dilation is k and the center is (0,0), then

(x,y)\rightarrow (kx,ky)

Since the scale factor is 2.4, therefore

(x,y)\rightarrow (2.4x,2.4y)

From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are

P(2,-2)\rightarrow P'(2.4(2),2.4(-2))

P(2,-2)\rightarrow P'(4.8,-4.8)

Therefore the coordinates of P' are (4.8,-4.8).

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First, how many pounds are equal to 1 ton?  2000

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So, the cost to move is $1,400

Yep. It's that simple. :)

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Tanvi runs 7.38 kilometers every morning. One day, she runs 0.73 kilometers and then
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Answer:

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3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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