We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
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X = 13 because if NK = 23 that means the equation is x-6+9+2x-19 = 23 then you subtract 9 from each side of the equals sign and add the x’s together than add -6 to -19 and get a equation of 3x-25 = 14 then add 25 to each side and get 3x = 39 the divided 39 by 3 and get x = 13
Answer:
(0, −2) and (2, 0)
Step-by-step explanation:
Solutions are the points of intersection
50x11=550
579-550=29
29 bracelets will be in last box
Answer:
21
Step-by-step explanation:
multiple both sides by 7
v = 21
Check:
21/7 = 3
3 = 3