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Maurinko [17]
4 years ago
15

Please help!

Mathematics
2 answers:
eimsori [14]4 years ago
6 0

Answer:

13.33333333333333 hrs

Step-by-step explanation:

Wewaii [24]4 years ago
5 0
13 hours
200 divided by 15 = 13.33333333333333
So since this a long number I have to round.
Answer: 13 hours
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What is the factored form of the polynomial 27x2y-43xy2
iogann1982 [59]

Answer:

xy(27x - 43y)

Step-by-step explanation:

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3 years ago
The point of equidistant from the vertices of a triangle is its? ​
Luden [163]

Answer:

The CIRCUMCENTER of a triangle is the point in the plane equidistant from the three vertices of the triangle.

3 0
3 years ago
What are two ways that graphing a linear inequality is different from graphing a linear equation?
77julia77 [94]
One way is that an inequality can have a dotted or solid line and another way is that you shade one side of the on an inequality.
3 0
4 years ago
Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter
Lerok [7]

Answer:

There are no possible solutions

Step-by-step explanation:

Given:

Minimum number of coins Alexa has =28 coins

Number of quarters Alexa has = 17 quarters

Total amount in coins = $5.05 = 505 cents

Let number of dimes be = x coins

So we can have two inequalities.

1) Total number of coins

x+17\geq28\\  [Since minimum number of coins=28]

2) Total value of coins

10x+(25)(17)\leq505 [As 1 dime=10 cents and 1 quarter=25 cents]

10x+425\leq505

Solving inequality (1)

Subtracting both sides by 17.

x+17-17\geq28-17

∴ x\geq 11

Solving inequality (2)

Subtracting both sides by 425.

10x+425-425\leq505-425

10x\leq 80

Dividing both sides by 10.

\frac{10x}{10}\leq \frac{80}{10}

∴ x\leq 8

On combining both solutions

x\geq 11 and  x\leq 8 ,

we see that there are no possible solutions as number of dimes cannot be ≥11 and ≤8 at the same time.

7 0
3 years ago
-17 + 20 + (-3) = plz help
miss Akunina [59]

Answer:

Step-by-step explanation:

=0

7 0
3 years ago
Read 2 more answers
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