It’s should 5x^2+7x+3 in standard form
9514 1404 393
Answer:
274 mL
Step-by-step explanation:
Often medical solutions expressed as a percentage are not really a percentage as such. A percentage is the ratio of two quantities with the same units.
Here, the context given by the problem suggests the "25%" solution is really (25 g)/(100 mL). That is, the units are grams and milliliters--different units.
With that assumption, we want to find the volume (v) of solution needed to deliver 6 g of medicine. An appropriate proportion* is ...
v/(6 g) = (100 mL)/(25 g)
v = (6 g)(100 mL)/(25 g) = 24 mL
So, the total volume of the infusion is ...
250 mL +24 mL = 274 mL
_____
* The concentration is given in terms of g/mL, but we have used a proportion that is mL/g. The reason for that is we want the variable to be in the numerator of the ratio. The variable here represents volume, so we have written the proportion with volumes in the numerators.
Having the variable in the numerator means the equation can be solved in one step--by multiplying by its denominator.
Answer:
50 ft²
Step-by-step explanation:
If W is the width and L is the length, then:
L = W + 5
2L + 2W = 30
Solve the system of equations with substitution or elimination. Using substitution:
2(W + 5) + 2W = 30
2W + 10 + 2W = 30
4W = 20
W = 5
L = 10
The area of the rectangle is:
A = LW
A = 50 ft²
Answer:
If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line is a perpendicular bisector of the connecting line segments.
Step-by-step explanation:
Answer:
dy/dx=8
Step-by-step explanation:
note this differentiating a constant you get zero for that of a function like 8x you would use the index or power of x to multiply the coefficient of the x after substrate 1 from the power of the x putting that in writing for the above question we get
y'=dy/dx=(8*1)x^(1-1) - 0
y'=dy/dx=8x^0
y'=dy/dx=8
