Simplify the expression where possible. (r^-3 s^2 t)^4

Mathematics

2 answers:

lisabon 2012 [21]4 years ago

8 0

Answer:

$\frac{(s^8t^4)}{r^{12}}$

Step-by-step explanation:

Assuming that you tried to write:

$(r^{-3} s^2 t)^4,$

we can multiply the 4 on the outside of the parenthesis to all the terms. Multiplying, we get

$(r^{-12}s^8t^4)$

Because you don't want any negative powers in the top, we can move it down to get:

$\frac{(s^8t^4)}{r^{12}}$

Eduardwww [97]4 years ago

8 0

Answer:

there is no sign in between the two terms in the parenthese, maybe a google search on the properties of exponents would help because that's what this seems like

Step-by-step explanation:

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Rainbow [258]

First we need to calculate the number of people wearing a blue shirt,
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7 0

3 years ago

What is the value of angle x°?

erastova [34]

Answer:

$64^\circ$

Step-by-step explanation:

Please refer to the attached figure for the labeling and construction in the given figure:

Given that minor angle of arc AB is $116^\circ$ .

Or in other words, we can say that angle subtended on the center O by the arc is $116^\circ$ .

Now, PA and PB are the tangents so, if we join the center of circle O with A and B, the angles formed are right angles.

i.e.

$\angle PAO = 90^\circ\\\angle PBO = 90^\circ$

Now, we know that sum of internal angles of a quadrilateral is equal to $360^\circ$ .

Here, we have the quadrilateral AOPB.

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