Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
In a circle, the arc is two times the length of the angle.
EFG = 98°
98 x 2 = 196
Minor arc EG = 196°
Hopefully this helps :)
99 and 59
X=big number
X-40 = small
X+ x-40 =158
2X -40=158
2X =198
X=99. Big number is 99
99-40 =59
99+59=158
Answer:
c o s t = x \displaystyle P: \text{cos}t=x P:cost=x.
Step-by-step explanation:
The cosine of t is equal to the x-coordinate of point P
Sadly there is no way to graph properly on this website.
