1=5. 2=10 3=15. 4=10 5=x. what does x equally

Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul

Ivahew [28]

Answer:

a) $P(X \leq 4)$

And we can find this using the cumulative distribution function:

$P(X \leq 4) = F(4) = 0.9$

b) $P(X > 7)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0$

c) $P(X \leq 5)$

And we can find this using the cumulative distribution function:

$P(X \leq 5) = F(5) = 0.9$

d) $P(X > 4)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1$

e) $P(X \leq 2)$

And we can find this using the cumulative distribution function:

$P(X \leq 2) = F(2) = 0.7$

Step-by-step explanation:

For this case we have the following cumulative distribution function:

$F(x) = 0 , x$

$F(x) = 0.7, 1 \leq x$

$F(x) = 0.9, 4 \leq x$

$F(x) = 1, x \geq 7$

Part a

We want this probability:

$P(X \leq 4)$

And we can find this using the cumulative distribution function:

$P(X \leq 4) = F(4) = 0.9$

Part b

We want this probability:

$P(X > 7)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0$

Part c

We want this probability:

$P(X \leq 5)$

And we can find this using the cumulative distribution function:

$P(X \leq 5) = F(5) = 0.9$

Part d

We want this probability:

$P(X > 4)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1$

Part e

We want this probability:

$P(X \leq 2)$

And we can find this using the cumulative distribution function:

$P(X \leq 2) = F(2) = 0.7$

7 0

3 years ago

(27a⁶b³c⁹)⅓<br> How to solve

LenaWriter [7]

Answer:

9a⁶b³c⁹

Step-by-step explanation:

Just divide the 27 by 3 since 27a⁶b³c⁹ is a single number

8 0

4 years ago

Chris wanted to transform the graph of the parent function Y= cot (x) by horizontally compressing it so that it has a period of

pashok25 [27]

Answer:

He didn't calculate the b-value correctly.

Step-by-step explanation:

The given parent function is:

$y = \cot(x)$

The transformation is of the form:

$y =a \cot(bx + c) + d$

The period is given by

$\frac{\pi}{b}$

If we want the new function to have a period of

$\frac{2}{\pi}$

Then we solve the following equation for b.

$\frac{\pi}{b} = \frac{2}{\pi}$

$b = \frac{ {\pi}^{2} }{2}$

$- \frac{c}{b}$

will translate the graph horizontally to the right by

$\frac{c}{b}$

units.

+d shifts the graph up by d units.

The new function then becomes:

$y = \cot( \frac{ {\pi}^{2} }{2} (x - \frac{\pi}{4} ) )+1$

3 0

3 years ago

Read 2 more answers

Sweet Dreams Bakery sells apple, cherry, and pumpkin pies. Yesterday, the bakery sold 20 more apple pies than cherry pies, and 1

podryga [215]

Answer:

There were 45 pies sold in all.

Step-by-step explanation:

10 + 15 = 25

25 + 20 = 45

3 0

2 years ago

I got 6 and 7 I just need 8 and 9.

Ivahew [28]

Answer:

8) 92°

9) 44°

Step-by-step explanation:

8) 92°

9) 44°

8 0

3 years ago