Question

The length of a rectangular piece of steel is 4 meters less than double the width. The perimeter of the steel is 22 meters find the length and width of steel

Answer 1

Answer:

$Length= 6 m \\ Width = 5m$

Step-by-step explanation:

Let the width of the piece be '$W$'

Length of the piece be '$L$'

According to the given statement

                $Length=2W-4$

Perimeter = 22 m

Perimeter of the rectangular sheet=

                                 $2(L+W)\\ 22= 2(2W-4+W)\\ 22=2(3W-4)\\ 11=3W-4\\ 3W=11+4\\ 3W=15\\ W= 5$

   $Length=2W-4$

                $=2(5)-4\\=10-4\\Length=6 m$

   $Length= 6 m \\ Width = 5m$

Answer 2

Answer: length = 6 meters

Width = 5 meters

Step-by-step explanation:

Let L represent the length of the rectangular piece of steel.

Let W represent the width of the rectangular piece of steel.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of the steel is 22 meters. This means that

2(L + W) = 22

Dividing through by 2, it becomes

L + W = 11 - - - - - - - - - - - -1

The length of a rectangular piece of steel is 4 meters less than double the width. This means that

L = 2W - 4

Substituting L = 2W - 4 into equation 1, it becomes

2W - 4 + W = 11

2W + W = 11 + 4

3W = 15

W = 15/3

W = 5

L = 2W - 4 = 2 × 5 - 4

L = 10 - 4

L = 6