Answer: It is TRUE. A point in a linear equation can be the solution to said equation.
Answer:
y=-2/3x+20/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-6)/(4-1)
m=-2/3
y-y1=m(x-x1)
y-6=-2/3(x-1)
y=-2/3x+2/3+6
y=-2/3x+2/3+18/3
y=-2/3x+20/3
Answer:
A = 1.5 π in² ≈ 4.7 in²
Step-by-step explanation:
the area (A) of the sector is calculated as
A = area of circle × fraction of circle
= πr² × 
= π × 3² × 
= 9π × 
= 1.5π in²
≈ 4.7 in² ( to the nearest tenth )
Answer:
y = 2x + 12
Step-by-step explanation:
You can check this by plugging any of the values from the table into the equation. You can find the answer by finding the slope and then using that to find the y-intercept.
y2-y1/x2-x1
16-14/2-1 = 2/1 = 2. So our slope equals 2.
If we set x = 0 to find our y-intercept, and we know that we have a slope of 2 we can subtract 2 from 14 to get the y-intercept.
14-2 = 12. --> (0, 12) which is true because we know that the slope is 2.