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pychu [463]
3 years ago
5

A cat weighs 3.5 ounces when born. The cat grows 0.5 ounces each week. After

Mathematics
2 answers:
Oksana_A [137]3 years ago
6 0

Answer: 26 weeks

Step-by-step explanation:

This is an example of an arithmetic sequence.

The first term = 3.5

common difference = 0.5

Using the formula for calculating the nth term of an arithmetic sequence :

t_{n} = a + (n - 1 ) d

Therefore :

16.5 = 3.5 + ( n - 1 ) x 0.5

16. 5 = 3.5 + 0.5n - 0.5

16.5 = 3 + 0.5n

16.5 - 3 = 0.5n

13.5 = 0.5n

n = 13.5/0.5

n = 27

Therefore , it will take the cat (n-1)  weeks to weigh 16.5 ounce, which will be 27 - 1 = 26

check:

3.5 + 26 ( 0.5)

= 3.5 + 13

= 16.5

ehidna [41]3 years ago
4 0

Answer:

10 weeks

Step-by-step explanation:

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7 0
3 years ago
Plz help me with math again am so bad at it
lianna [129]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
2. There are some benches in a classroom. If 4 students sit on each bench then 3 benches
NARA [144]

Answer: There are 48 students in the class.

Step-by-step explanation:

Let the number of students = S

Let the number of benches = B

<em>If 4 students sit on each bench, 3 benches are left vacant.</em>

S = 4(B - 3)

S = 4·B - 12 } Equation 1

<em>If 3 students sit on each bench, 3 students still standing.</em>

S = 3·B + 3 } Equation 2

We can match the two equations because they both indicate the same number of students.

4B - 12 = 3·B + 3

on solving this

4·B - 3·B = 3 + 12

B = 15 → number of benches

That is the number of benches, therefore substituting the value for B in equation 1

S = 4·B - 12 Equation 1

S = 4·15 -12

S = 60 - 12 = 48 → number of students

Answer: There are 48 students in the class.

<h3>Verification</h3>

There are 48 students and 15 benches.

<em>If 4 students sit on each bench, 3 benches are left vacant.</em>

48students ÷ 4students/bench = 12 benches are occupied and left 3 vacant benches.

<em>If 3 students sit on each bench, 3 students still standing.</em>

<h3 />

15benches * 3 students/bench = 45 students are sitting and 3 students remain standing.

<h3>Checked!!</h3>

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8 0
3 years ago
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

7 0
3 years ago
Select the sets that are not a functions.
balandron [24]

Answer:

I think it's D and E

Step-by-step explanation:

6 0
3 years ago
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