A cat weighs 3.5 ounces when born. The cat grows 0.5 ounces each week. After
2 answers:
Answer: 26 weeks
Step-by-step explanation:
This is an example of an arithmetic sequence.
The first term = 3.5
common difference = 0.5
Using the formula for calculating the nth term of an arithmetic sequence :
= a + (n - 1 ) d
Therefore :
16.5 = 3.5 + ( n - 1 ) x 0.5
16. 5 = 3.5 + 0.5n - 0.5
16.5 = 3 + 0.5n
16.5 - 3 = 0.5n
13.5 = 0.5n
n = 13.5/0.5
n = 27
Therefore , it will take the cat (n-1) weeks to weigh 16.5 ounce, which will be 27 - 1 = 26
check:
3.5 + 26 ( 0.5)
= 3.5 + 13
= 16.5
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Answer:
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Step-by-step explanation:
Set up a system of equations.
Let be "b" the time Bailey family's sprinkler was used and "h" the time Harris family's sprinkler was used.
Then:
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Answer:
The number of adult tickets are 33 and the number of student tickets are 21 .
Step-by-step explanation:
As
The number of adult tickets x and the number of student tickets y.
As given
A carnival sold tickets for $1.50 for adults and $1.00 for students.
There were 54 tickets sold for a total of $70.50.
Equations becomes
x + y = 54
1.50x + 1.00y = 54 × 70.50
Simplify the above
150x + 100y =7050
Two equations are
x + y = 54
150x + 100y =7050
Multiply x + y = 54 by 150 from 150x + 100y =7050
150x - 150x + 100y - 150y = 7050 - 8100
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50y = 1050
y = 21
Putting the value of y in the equation .
x + 21 = 54
x = 54 - 21
x = 33
Therefore the number of adult tickets are 33 and the number of student tickets are 21 .