Question

Find the value of x and y that satisfy both the equalities x/y=2/3 and y/24=3/4 .

Answer 1

x=12 and y=18 satisfies both the equalities.

Step-by-step explanation:

Given equations are;

x/y = 2/3   Eqn 1

y/24 = 3/4   Eqn 2

Multplying by 24 on both sides of Eqn 2

$24*\frac{y}{24}=\frac{3}{4}*24\\\frac{24y}{24}=\frac{72}{4}\\y=18$

Putting y=18 in Eqn 1;

$\frac{x}{18}=\frac{2}{3}$

Multiplying both sides by 18

$18*\frac{x}{18}=\frac{2}{3}*18\\\frac{18x}{18}=\frac{36}{3}\\x=12$

Putting both values in Eqn 1

$\frac{12}{18}=\frac{2}{3}$

As 12 and 18 are multiples of 6;

$\frac{2}{3}=\frac{2}{3}$

x=12 and y=18 satisfies both the equalities.

Keywords: fraction, division

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