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2 years ago

6

Help me..........

1 answer:

beks73 [17]2 years ago

4 0

Y+5x=-3 step-by-step

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3 years ago

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the area of a square can be quadrupled by increasing the side length and width by 4 inches. what is the side length?

vodomira [7]

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3 years ago

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If x varies directly as y, find x when y = 8.<br> x = -4 when y = 10<br> X =

timurjin [86]

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2 years ago

-2 - 5 =? I’ll mark BRAINLIEST!!!

masya89 [10]

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3 years ago

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Each side of a square is increasing at a rate of 2 cm/s. at what rate is the area of the square increasing when the area of the

faltersainse [42]

Let x(t) = the length of a side of the square (cm) at time t (s).
The rate of change of x is given as
$\frac{dx}{dt} =2 \, \frac{cm}{s}$

The area (cm²) at time t is
A = x²

The rate of change of the area with respect to time is
$\frac{dA}{dt} = \frac{dA}{dx} \frac{dx}{dt} =2 \frac{dA}{dx} =2(2x)=4x \, \frac{cm^{2}}{s}$

When A = 9 cm², then x = √9 = 3cm. Hence obtain
$\frac{dA}{dt} = 4(3) = 12 \, \frac{cm^{2}}{s}$

Answer: 12 cm²/s

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3 years ago