Answer:
# Code in Python
dictionary={'A':1,'B':2,'C':3,'D':4}
other_dictionary={}
for keys in dictionary:
if dictionary[keys]&1==1:
temp=dictionary[keys]*dictionary[keys]-10*10
other_dictionary[keys]=temp
else:
other_dictionary[keys]=dictionary[keys]
print(other_dictionary)
assert other_dictionary
Explanation:
- Initialize a sample example dictionary and other_dictionary.
- Do a binary comparision for checking odd number
.
- Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
- For even: store the original value (from dictionary).
Answer:
Explanation:
This is unsolvable if you have no variable substitutes
Thesaurus is a tool use to find the synonym of the of a word.
Here's the way to use the thesaurus in the word processor.
=> highlight the word, then right-click, Navigate to synonyms and the words will display.
The answer to this is B=MODE(A1:A65)
Answer:
The quality of service basically provide the sufficient quality in the IP network and it is also known as traffic shaping. As, it assign the priority to every device and the services in the network. It basically recognize the several types of the traffic moving in the network.
The implementation of quality of service is basically done in many network applications by reserve the bandwidth and specific path in the network system.
The various network device control the packet flow so that the network resources can easily accept packets in the network.