this picture would help you man stay strong
Answer:
Step-by-step explanation:
Socratic had the answer on there I think
This is a system of equations problem. Set up the 2 equations like so: If the angles are complementary then they add up to 90, therefore, a + b = 90. We also know that a is 16 more than b. The word "is" means equals and "more" is addition. Therefore, a is 16 more than b is "a = b + 16". Now sub in that value of a (b + 16) into the first equation and solve for b. Then back-substitute to solve for a. (b + 16) + b = 90 so 2b + 16 = 90 and 2b = 74. So b = 37. If b = 37, then a + 37 = 90 and a = 53. Check yourself to make sure that 37 + 53 add up to equal 90 (they do, just get used to checking yourself for accuracy).
The given parallelogram is a rhombus
Solution:
Option A: Rhombus
Let us recall the property of rhombus.
- Diagonals bisect each other at right angles.
- Opposite angles are congruent.
Here diagonals bisect the angles equally each 72°.
Opposite angles are congruent(72° + 72° = 144°).
Hence the given parallelogram is a rhombus.
Option B: Rectangle
Let us recall the property of rectangle.
- Diagonals bisect each other.
- All the angles of a rectangle are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a rectangle.
Option C: Square
Let us recall the property of square.
- Diagonals bisect each other.
- All the angles of a square are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a square.
