Below are I assume the choices, it can be found elsewhere:

A. 15x+10y≥250

B. x+y≤250

C. x+y≥20

D. 15x+10y≥20

E. x+y≤20

<span>F. 15x+10y≤250
</span>
The inequalities that represent constraints for this situation is 15x+10y<=250 and <span>x+y>20. Thank you for posting your question here. I hope the answer helps. </span>

4 0

3 years ago

Read 2 more answers

Why is 3/4 greater thab 11/16 how can i be sure

Delicious77 [7]

You can make them have the same denominator and then compare

$( \frac{3}{4}) ( \frac{16}{16}) = \frac{48}{64}$

$(\frac{11}{16})( \frac{4}{4}) = \frac{44}{64}$

so as you can see, $\frac{3}{4} is \frac{4}{64} bigger than \frac{11}{16}$

5 0

3 years ago

Find the coordinates of the midpoint of the segment connecting points (-3,-6) and ( 2,5)

Pavlova-9 [17]

(x2 subtracted by x1 divided by 2, y2 subtracted by y1 divided by 2) is the midpoint formula.
(2-3/2, 5-6/2)= (-1/2, -1/2) which is the answer/

3 0

3 years ago