Decimals are a number and a dot and more numbers
we know that
the volume of a solid oblique pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
in this problem we have that
B is a square

where
<u>
</u>
so


substitute in the formula of volume
![V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2Ax%5E%7B2%7D%2A%28x%2B2%29%5C%5C%20%5C%5CV%3D%5Cfrac%7B1%7D%7B3%7D%2A%5Bx%5E%7B3%7D%20%2B2x%5E%7B2%7D%5D%5C%20cm%5E%7B3%7D)
therefore
<u>the answer is</u>
![V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2A%5Bx%5E%7B3%7D%20%2B2x%5E%7B2%7D%5D%5C%20cm%5E%7B3%7D)
we conclude that the center of the circle is the point (-5, 0).
<h3>How to find the center of the circle equation?</h3>
The equation of a circle with a center (a, b) and a radius R is given by:

Here we are given the equation:

Completing squares, we get:

Now we can add and subtract 25 to get:

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).
If you want to learn more about circles:
brainly.com/question/1559324
#SPJ1
Answer:
120 blocks total
Step-by-step explanation:
All of the little cubes have side length 2" Thus, the 11" height of the box cannot be used entirely: we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.
Start at the bottom of the box. The dimensions of the bottom are 12" by 8". Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide. We can add 3 more such rows to fill the available 8" width of the box bottom. That's 6*4, or 24 blocks.
We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.
5 layers times 24 blocks per layer comes to 120 blocks total.