I will assume that everything after the radical sign is under the sign...
6√(64x^4y^2)
6√(8^2(x^2)^2(y^2)) removing all of the perfect squares...
6*8*x^2*y
48x^2y
Answer:
cos13=0.97 and sin0=0
Step-by-step explanation:
cos(13)
put in calculator and get 0.97
and do the same for sin(0).
sin(0)
0.
Answer:
IQR=13 im pretty sure
Step-by-step explanation:
Answer:
1 3 ...................rotate 3 and it is the same as 1