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neonofarm [45]
3 years ago
9

Find the area of the shaded region

Mathematics
1 answer:
Margarita [4]3 years ago
8 0
I have no information to help you with. Try asking again, but with a photo
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Max delivered 8520 pieces of mail in one year if he delivers the same number of pieces of mail each month about how many pieces
joja [24]
The ans is 1400 over 2 mo.
5 0
3 years ago
Can someone please help me to find the remainder when f(x) is divided by (x^2-4)?
yuradex [85]

Answer:

Step-by-step explanation: Given : f(x)=x

4

−3x

2

+4

f(2)=(2)

4

−3(2)

2

+4

=16−12+4=8

8 0
2 years ago
1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in
scZoUnD [109]

Answer:

Step-by-step explanation:

a) \int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

Substitute limits to get

= \frac{1}{3}

Thus converges.

b) 10th partial sum =

\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

=\frac{-1}{3} (0.001-1)\\= 0.333

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0
3 years ago
Find the volume of a pyramid with a square base, where the side length of the base is
irina [24]

The volume of the pyramid is  167.6 cube inch (approx).

Step-by-step explanation:

Given,

Each length (l) of the base of the pyramid = 8.3 in

Height(h) of the pyramid = 7.3 in

To find the volume of the pyramid.

Formula

Volume of the pyramid = \frac{1}{3}×area of the base×height

Area of the base = l²

Now,

The volume of the pyramid =  \frac{1}{3}×l²×h

=  \frac{1}{3}×8.3²×7.3 cube inch = 167.6 cube inch (approx)

8 0
3 years ago
An arch is in the shape of a parabola. It has a span of 100 feet and a maximum height of 25 ft.
faltersainse [42]

Answer:

y=-\frac{1}{100}(x-50)^2+25

the height of the arch 10 feet from the center is 24 feet

Step-by-step explanation:

An arch is in the shape of a parabola. It has a span of 100 feet, the vertex lies at the center 50 and the maximum height of 25 ft.

Vertex at (50,25)

vertex form of the equation is

y=a(x-h)^2+k, (h,k) is the center

y=a(x-50)^2+25

the parabola starts at (0,0) that is (x,y)

0=a(0-50)^2+25

subtract 25 from both sides

-25=a(-50)^2

-25=a(2500)

divide both sides by 2500

a=-\frac{1}{100}

y=-\frac{1}{100}(x-50)^2+25

the height of the arch 10 feet from the center.

center is at 50, 10 feet from the center so x=40 and x=60

y=-\frac{1}{100}(40-50)^2+25

y=24

the height of the arch 10 feet from the center is 24 feet

4 0
3 years ago
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