Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.
Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.
Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7
Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18
Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.
Answer: 37,39,41,43
Standard form of given question :8.5016012×10^7
Answer:
The answer is 
Step-by-step explanation:
To find how many gigabytes there are in 1 megabyte, we need to divide 1 megabyte by one gigabyte.
To divide exponents, you subtract them.
Then divide 10/10.
Your answer is . (which equals 0.001)
I hope this helps! :)
~Peredhel
Answer:
9
Step-by-step explanation:
9*4 = 36
9*9 = 81
divide both by 9 and you get 4:9
