<span>A. 4. EFI = HFG 4. Vertical angles
5. EFI = HFG 5. SAS
is this it?</span>
Answer:
-6
Step-by-step explanation:
The slope of a line is given with the formula
Using the first two points, (-2, 8) and (-1, 2), we have
m = (2-8)/(-1--2) = -6/(-1+2) = -6/1 = -6
Answer:
C. <em>c</em> is less than zero
Step-by-step explanation:
The parent radical function y=x^(1/n) has its point of inflection at the origin. The graph shows that point of inflection has been translated left and down.
<h3>Function transformation</h3>
The transformation of the parent function y=x^(1/n) into the function ...
f(x) = a(x +k)^(1/n) +c
represents the following transformations:
- vertical scaling by a factor of 'a'
- left shift by k units
- up shift by c units
<h3>Application</h3>
The location of the inflection point at (-3, -4) indicates it has been shifted left 3 units, and down 4 units. In the transformed function equation, this means ...
The graph says the value of c is less than zero.
__
<em>Additional comment</em>
Apparently, the value of 'a' is 2, and the value of n is 3. The equation of the graph seems to be ...
f(x) = 2(x +3)^(1/3) -4
Option A. 150 m 3 is the correct one
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
