Question

Two automobiles leave the same city simultaneously and both head towards another city. The speed of one is 10 km/hour greater than the speed of the other, and this is why the first automobile arrives at the destination 1 hour before the other. Find the speed of both automobiles knowing that the distance between the two cities is 560 km.

Answer 1

Answer:

5091 Km/hr and 505 km/hr

Step-by-step explanation:

Speed = Distance / Time

Let the speed of first automobile be 'x' and that of the second be 'y'

Since speed of one is 10 times greater than the other. therefore;

⇒ x = 10 y

also let time for faster automobile be 'T' and time for slower auto mobile be 't'

Since first arrive one hour earlier than second, therefore;

⇒ t = T + 1

⇒ For first automobile; $x X T = 560$ ; substituting for 'x' and 'T'. Therefore;

⇒ $10y (t+1) = 560$

⇒ For Second automobile; $y X t = 560$

⇒ $y = \frac{560}{t}$

⇒ $10(\frac{560}{t})(t + 1) = 560$

⇒ 5600 + $\frac{5600}{t}$ = 560

⇒ 5600 - 560 =  -  $\frac{5600}{t}$

⇒ t = 1.11 hr

also ; T = 1.11 - 1 = 0.11 hr

Speed of 1st auto  = 560/0.11 = 5091 km /hr

Speed of 2nd auto = 560/1.11 = 505 km/hr