Answer:
Does February March?.... NO, but APRIL MAY
Step-by-step explanation:
Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
\Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
Five kids can be given cookies in (10 + 5 - 1) C (5 - 1) = 14 C 4 = 1,001 ways.
A = allowance
(1/2)a = what have left after Monday
(1/2(1/2)a = what you have after Tuesday
(1/2)(1/2)(1/2)a = what you have after Wednesday.
Doing the multiplication.
(1/8)a = what you have left.
You have 1/8 of what you had at the start.
It would be 50 times because 15 divided by 3 is 5 and you just add your 0 back and get 50! hope this helps!
Answer:
![4ln [\frac{x^2 (x^3-1)}{x-5}]](https://tex.z-dn.net/?f=%204ln%20%5B%5Cfrac%7Bx%5E2%20%28x%5E3-1%29%7D%7Bx-5%7D%5D)
Step-by-step explanation:
For this case we have the following expression:
![4[ln(x^3-1) +2ln(x) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2B2ln%28x%29%20-ln%28x-5%29%5D)
For this case we can apply the following property:

And we can rewrite the following expression like this:

And we can rewrite like this our expression:
![4[ln(x^3-1) +ln(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2Bln%28x%5E2%29%20-ln%28x-5%29%5D)
Now we can use the following property:

And we got this:
![4[ln(x^3-1)(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%28x%5E2%29%20-ln%28x-5%29%5D)
And now we can apply the following property:

And we got this:
![4ln [\frac{x^2 (x^3-1)}{x-5}]](https://tex.z-dn.net/?f=%204ln%20%5B%5Cfrac%7Bx%5E2%20%28x%5E3-1%29%7D%7Bx-5%7D%5D)
And that would be our final answer on this case.