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ale4655 [162]
2 years ago
12

Mrs. Bailey gives a test, and her students’ scores range from 30 to 70. She decides to curve the scores, so that they range from

65 to 95. Let "x" be an original score, and "y" be a curved score. Using the ordered pairs (30,65) and (70,95), write the equation in slope/intercept form that she should use to curve the test scores.
Mathematics
1 answer:
Harman [31]2 years ago
8 0

Answer:

f(x) = x*3/4 + 42.5

Step-by-step explanation:

The original difference between the pair is 70 - 30 = 40

The new difference between the pair is 95 - 65 = 30

Since the differences are not the same, Mrs Bailey must first perform a (slope) multiplication by a factor of 30/40 or 3/4

Then 30 * 3/4 = 22.5

Then she can shift the scores up by 65 - 22.5 = 42.5 in order to get the range from 65 to 95

Therefore, f(x) = x*3/4 + 42.5. We can test that

f(30) = 30*3/4 + 42.5 = 65

f(70) = 70*3/4 + 42.5 = 95

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Kelly walked 3 miles.Abby walk 3/4 of a mile how far did they walk in all
timofeeve [1]

Answer:

3 3/4

Step-by-step explanation:

Add the two numbers:

3 + 3/4 = 3 3/4

3 3/4 is the amount walked in all.

~

8 0
3 years ago
If √2 = 1.414 then the value of 5+√2 / 5-√2 is
Gala2k [10]

Answer:

1.787

Step-by-step explanation:

\\  \sf \frac{5 +  \sqrt{2} }{5 -  \sqrt{2} }  \times  \frac{5 +  \sqrt{2} }{5  +   \sqrt{2} }

\\   \sf =  \frac{(5 +  \sqrt{2}) }{5 -  \sqrt{2} }  \times  \frac{(5 +  \sqrt{2}) }{5 +  \sqrt{2} }

\\  \sf =  \frac{25 + 5 \sqrt{2 } + 5 \sqrt{2} + 2  }{( {5})^{2}  - ( \sqrt{ {2}})^{2} }

\\  \sf =  \frac{27 + 10 \sqrt{2} }{25 - 2}

\\  \sf =  \frac{27 - 10 \sqrt{2} }{23}

Now putting the value of√2

\\  \sf =  \frac{27 + 10 \times 1.414}{23}

\\  \sf =  \frac{27 + 14.14}{23}

\\  \sf =  \frac{41.14}{23}

\\ \sf = 1.787

3 0
2 years ago
The data shown represent the number of runs made each year during Bill Mazeroski’s career. Check for normality.
const2013 [10]

Answer:

The given data is not normal.

Step-by-step explanation:

We are given the following data:

30, 59, 69, 50, 58, 71, 55, 43, 3,  66, 52, 56, 62, 36, 13, 29, 17, 31

Condition for normality:

Mean = Mode = Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{800}{18} = 44.44

Mode is the most frequent observation of the data.

Since all the value appeared once, there is no mode.

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 3, 13, 17, 29, 30, 31, 36, 43, 50, 52, 55, 56, 58, 59, 62, 66, 69, 71

Median =

=\dfrac{9^{th}+10^{th}}{2} = \dfrac{50+52}{2}=51

Since the mean, mode and median of data are not equal, the data is not normal.

7 0
3 years ago
Arleen has a gift card for a local lawn and garden store. She uses the gift card to rent a tiller for 4 days. It costs $35 per d
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She has $149 less of what she had on the gift card.
5 0
3 years ago
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Answer:

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Solve for v  by simplifying both sides of the equation, then isolating the variable.

4 0
3 years ago
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