Answer:
The data can be modeled using linear equatins, because there's the same amount of population for fish A (+20 per year) and fish B (+30 per year) every year.
This is a sum that needs understanding the starting and the ending number first. then you should understand that between the starting and the ending number there has to be pairs of numbers with a difference of 0.75.
The numbers are:
10.75, 11.50, 12.25, 13.00, 13.75, 14.50.
I think the mean of variable a is 4
Add 4 to both sides
w = -6
His new balance will be $805.8915
<span>4332.75 * 18.6%</span>
