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const2013 [10]
3 years ago
5

Evaluate the expression 4−(1−4)−2 =

Mathematics
2 answers:
Dominik [7]3 years ago
6 0

You do 4-(-3)-2 then you get

4+3-2 then u get

5

Cloud [144]3 years ago
3 0

Parentheses first. 1-4= -3. 4-3=1. 1-2=-1.

The answer is -1.

You might be interested in
Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr
julia-pushkina [17]

Answer:

A. 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

Oliver's Interviewees

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

 

Cross multiply

52.8 were 9th-graders interviewed by Oliver

Jenny's Interviewees

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

 

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =  

 

Cross multiply  

35 students were 10th-graders interviewed by Jenney.  

Total calculation

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

Therefore, there are 36 more 10th than 9th.

For more information, visit: brainly.com/question/23490909

7 0
3 years ago
Help answer please!!
12345 [234]

Answer:

h = 19.7 ft.

Step-by-step explanation:

Use the Pythagoras Theorem

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\\\(20)^2=(3.5)^2+(h)^2\\400=12.25+h^2\\400-12.25=h^2\\387.75=h^2\\

Now we take square root on both sides,

\sqrt{387.75} =\sqrt{h^2}\\19.69=h\\h=19.7\ ft\\

so the value of h equals 19.7 ft.

6 0
3 years ago
the seventh grade class is putting on a variety show to raise money. it cost 700 dollars to rent the banquet hall that they are
nexus9112 [7]

Answer:

Since the question is partial, i will assume 2 scenarios:

They need to raise 1000 income

They need to make 1000 as profit

If $1000 as income:

Each ticket costs $15, so  tickets would bring them $1000 income. Fractional ticket is not possible, so rounding gives us 67 tickets as the answer.

If $1000 as profit:

Their cost of renting is $700. We know that .

So, . So, to raise $1700, we need  tickets. Fractional ticket is not possible, so rounding gives us 114 tickets as the answer.

ANSWER:

If need to raise atleast $1000 as income, they need to sell 67 tickets.

If need to raise atleast $1000 as profit, they need to sell 114 tickets.

The most probable answer would be 114 tickets

PLZ MARK ME BRAINLIEST

4 0
3 years ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
$700 is invested at 4% per annum. How long will it take for the amount to reach $784?​
Blababa [14]

Answer:

3yrs

Step-by-step explanation:

Given parameters:

Capital = $700

Percentage interest  = 4% per annum

Unknown:

Time it will take for amount to be  = $784

Solution:

To find the simple interest on an amount;

        I = \frac{PRT}{100}

P is the principal

R is the rate

T is the time

I is the interest

    Insert the parameters:

        I  = \frac{700x 4 x T}{100}

        I = 28T

So;

   At the end of the duration:

       Principal + Interest  = Amount

          700+28T = 784

                   28T = 784 - 700

                   28T = 84

                       T = 3yrs

5 0
3 years ago
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