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antoniya [11.8K]
3 years ago
9

Peter is reading a 193-page book. He has read three pages more than one-fourth of the number of pages he hasn’t yet read. How ma

ny pages has he not yet read?
Mathematics
2 answers:
viva [34]3 years ago
5 0
N + n/4 + 3 = 193
5n/4 = 190
n = 152
At 8 pages per day it will take 152 pages/ 8 pages/day = 19 days
FinnZ [79.3K]3 years ago
5 0
He has not read 152 pages.

If y is the number of pages he has not read and x is the number of pages he has read, then:

x+y=193
x=1/4y+3 (the number of pages he has read is three pages more than one fourth the number of pages he hasn't read)

Since we have two equations, solving for one variable will allow us to substitute that value into the other equation. Since x is already isolated in the second equation, we will use that, substituting the value of x from the second equation into the first.

(1/4y+3)+y=193
5/4y+3=193
5/4y=190
y=152
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Please someone help me with this word problem for my math class T.T
olga55 [171]

Answer:

<u>Perimeter</u>:

= 58 m (approximate)

= 58.2066 or 58.21 m (exact)

<u>Area:</u>

= 208 m² (approximate)

= 210.0006 or 210 m² (exact)

Step-by-step explanation:

Given the following dimensions of a rectangle:

length (L) = \sqrt{252} meters

width (W) = \sqrt{175} meters

The formula for solving the perimeter of a rectangle is:

P  = 2(L + W) or 2L + 2W

The formula for solving the area of a rectangle is:

A = L × W

<h2>Approximate Forms:</h2>

In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.  

13² = 169

14² = 196

15² = 225

16² = 256

Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width).  We can use these values to approximate the perimeter and the area of the rectangle.

P  = 2(L + W)

P = 2(13 + 16)

P = 58 m (approximate)

A = L × W

A = 13 × 16

A = 208 m² (approximate)

<h2>Exact Forms:</h2>

L = \sqrt{252} meters = 15.8745 meters

W = \sqrt{175} meters = 13.2288 meters

P  = 2(L + W)

P = 2(15.8745 + 13.2288)

P = 2(29.1033)

P = 58.2066 or 58.21 m

A = L × W

A = 15.8745 × 13.2288

A = 210.0006 or 210 m²

8 0
2 years ago
Two rectangles have a area of 81 square inches. Name two possible perimeters for the rectangles ​
jeka94

Answer:

3, 27 and 9,9

Step-by-step explanation:

3*27 = 81

9*9=81

Technically you could say 1 and 81 but those two answers fit the most.

3 0
3 years ago
Please help!! I’ll mark brainliest!
elena-14-01-66 [18.8K]

Answer:

Just from looking at the picture, I'm assuming that we're trying to find the terms that are like to the terms in the blue section.

1. 8c since both are in terms of c

2. 7t since both are in terms of t

3. 8r since both are in terms of r

4. -4n since both are in terms of n

5. xy since both are in terms of xy

6. 16 since both don't have any variables

7. 4sp since both are in terms of sp

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The revenue from selling x shirts is f(x) = 15x.
Virty [35]

Answer:

p(x) = 8x - 20

Step-by-step explanation:

revenue from selling x shirts is f(x) = 15x

The cost of buying x shirts is c(x) = 7x + 20

p(x) = f(x) - c(x)

To solve this, we need to substitute value of f(x) and c(x) in formula for p(x)

p(x) = f(x) - c(x)

p(x) = 15x -( 7x + 20)

=>  p(x) = 15x - 7x -20

=>  p(x) = 8x -20

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3 years ago
what is the critical f-value when the sample size for the numerator is six and the sample size for the denominator is four? use
lubasha [3.4K]

The critical f-value when the sample size for the numerator and the  denominator is given using a two-tailed test will be 0.12 and 14.88.

We have,

The sample size for the numerator = 6,

i.e.

Numerator degree of freedom = 6 - 1 = 5,

And,

The sample size for the denominator = 4,

i.e.

Denominator degree of freedom = 4 - 1 = 3

And,

We have to use a two-tailed test,

So,

The significance level = \frac{0.10}{2} = 0.05

And,

Now,

The test follows the F-distribution with (5, 3) degrees of freedom,

Now,

Using the F-table at significance level 0.05 and check for given degrees of freedom,

We get,

Critical f-values : 0.12 and 14.88

Hence, we can say that the critical f-value when the sample size for the numerator and the  denominator is given using a two-tailed test will be 0.12 and 14.88.

Learn more about critical f-value click here:

brainly.com/question/17164520

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