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3 years ago

Find the slope using the formula. (4, 19) and (2, 11)

Mathematics

1 answer:

Degger [83]3 years ago

7 0

Answer:

$m=4$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

(4, 19)

(2, 11)

Step 2: Find slope m

Substitute: $m=\frac{11-19}{2-4}$
Subtract: $m=\frac{-8}{-2}$
Divide: $m=4$

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You have 100 feet of fencing and decide to make a rectangular garden. What is the largest area enclosed

k0ka [10]

Answer:

625 ft^2

Step-by-step explanation:

Given

$P = 100$ --- perimeter

Required

The largest area

The perimeter is calculated as:

$P = 2 * ( L + W)$

So, we have:

$2 * ( L + W) = 100$

Divide both sides by 2

$L + W = 50$

Make L the subject

$L = 50 - W$

The area is calculated as:

$A= L * W$

Substitute $L = 50 - W$

$A= (50 - W) * W$

Open bracket

$A = 50W - W^2$

Differentiate with respect to W

$A' = 50 -2W$

Set to 0; to get the maximum value of W

$50 - 2W = 0$

Collect like terms

$-2W = -50$

Divide by -2

$W = 25$

So, the maximum area is:

$A = 50W - W^2$

$A = 50 * 25 - 25^2$

$A = 1250 - 625$

$A = 625$

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Assume that a student's alarm clock has a 11.2 % daily failure rate. What is the probability that the student's alarm clock w

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3 years ago

Amy and her three friends love to eat pizza for lunch. Amy's mother bakes

HACTEHA [7]

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Jill has a fraction of 1/2

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3 years ago

Expand the given power using the Binomial Theorem. (10k – m)5

agasfer [191]

Answer:

$(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

$(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}$

∵ The binomial is $(10k-m)^{5}$

∴ a = 10k , b = -m and n = 5

∴ $(10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}$

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ $(10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})$

∴ $(10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

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3 years ago