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Anon25 [30]
3 years ago
15

(Photo) Pls help me!

Mathematics
2 answers:
UNO [17]3 years ago
8 0

Answer: C

Step-by-step explanation:

A P E X

faltersainse [42]3 years ago
3 0
C, there are 3 options the first time, and after that, there are 3 options for each of those. So it would be C.
You might be interested in
Given f(x) = x^2 - 5x, find f(x-3)
Hoochie [10]

Answer:

f(x-3)= x^2 -11x +24

Step-by-step explanation:

We want to find an equivalent expression for f(x-3)

To do this, we can simply substitute every 'x' variable in f(x) by 'x-3'

Therefore f(x-3)= (x-3)^2 -5*(x-3)

Lets re arrange the expression by grouping terms.

f(x-3)=x^2 - 6x +9 -5x + 15

f(x-3)= x^2 -11x +24

3 0
3 years ago
Please help, and show me how you got the answer because i have to show for the answer thank you ❤️
snow_lady [41]
I tried my best for this I’m pretty for sure I remember doing this in school but I’m not for sure I hope this helped a little bit

6 0
3 years ago
A recipe for a smoothie calls for 0.75 pound of strawberries. If Kerry has 31.5 pounds of strawberries, how many batches of the
vodomira [7]

42 batches. 31.5 divided by .75 = 42.

5 0
2 years ago
HEEEEEEEEEEEEEEEEEEEEEEELP
Crank

Answer:

A is -2

B is 2

C is 4

Step-by-step explanation:

So just replace each letter with these numbers and do the math, hope this helps

4 1
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Akimi4 [234]

Answer:

25.6 units

Step-by-step explanation: From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

Read more on Brainly.com - brainly.com/question/12560433#readmore

8 0
3 years ago
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