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blsea [12.9K]
3 years ago
14

What approximate error rate should the manager expect for a worker who receives 6 hours of training?

Mathematics
1 answer:
mamaluj [8]3 years ago
6 0

Answer:

c.0.13

Step-by-step explanation:

You might be interested in
Reduce 22/30 to lowest terms and write the numerator in the blank. ___
schepotkina [342]

Answer:

11/15

Step-by-step explanation:

You would divide by 2 for each.

3 0
4 years ago
Convert the following inches to feet and inches <br>39 inches<br>42.5 inches<br>61 3/4 inches
9966 [12]
39 inches = 3 feet 3 inches
42.5 inches = 3 feet 6 1/2 inches
61 3/4 inches - 5 feet 1 3/4 inches
7 0
3 years ago
Are these two expressions equivalent?<br> 6 + 3 and 3 + 6
labwork [276]

Answer: Yes its equivalent

Step-by-step explanation:

6 + 3 =9 and 3 + 6= 9

9 = 9

You should know this smh

6 0
3 years ago
Conservationists tagged 120 ​black-nosed rabbits in a national forest in 1990. In 1991​, they tagged 240 ​black-nosed rabbits in
Sauron [17]

Answer:

Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.

Step-by-step explanation:

Given:

Population for rabbit obeys exponential law.

120 at 1990 and 240 1991 ...after 1 year time period

To Find:

After 9 year  time period how many rabbits will be there.

Solution:

Exponential law goes on present value and various value and time period and defined as ,

let Y be present value Y0 previous year value  and k exponential constant and t be time period.

So

Y=Y0e^(kt)

Here Y=240  ,Y0=120  t=1 year time period

So

240=120e^(k*1)

240/120=e^k

2=e^k

Now taking log on both side, [natural log]

ln(2)=ln(e^k)

ln(2)=kln(e)

k=ln(2)

k=0.6931

For t=9 year of time period

Y0=120,  t=9  ,k=0.6931

Y=Y0e^(k*t)

Y=120*e^(0.6931*9)

=120e^6.2383

=61438.48

=61438 rabbits

8 0
4 years ago
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 500(1.075)120x = 100.000
Volgvan

Answer:

The solution is:

x = 0.61

Step-by-step explanation:

The first step to solve this equation is placing everything with the exponential to one side of the equality, and everything without the exponential to the other side. So

500(1.075)^{120x} = 100000

(1.075)^{120x} = \frac{100000}{500}

(1.075)^{120x} = 200

To find x, we have to apply log to both sides of the equality.

We also have that:

\log{a^{x}} = x\log{a}

So

\log{(1.075)^{120x}} = \log{200}

120x\log{1.075} = 2.30

120x*0.03 = 2.30

3.77x = 2.30

x = \frac{2.30}{3.77}

x = 0.61

4 0
3 years ago
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