What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0

Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1

I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!

8 0

3 years ago

Please answer this question I need this urgent Help meeeee

iren [92.7K]

Answer:

$\frac{s}{2t}$

Step-by-step explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

$a^{x} *a^{y} = a^{x + y}$

So let's group like terms in the numerator:

$4r^{3} r^{-5} s^{-2} s^{-1}t$ We can add terms like in the example.

$4 r^{-2} s^{-3} t$

Let's rearrange the denominator.

$8r^{-2} s^{-4} t^{2}$

Now we have:

$\frac{4r^{-2} s^{-3}t}{8 r^{-2} s^{-4} t^{2} }$ Cancel like terms

4/8 = 1/2

$r^{-2} /r^{-2}$ = 1 So it cancels

$s^{-3} / s^{-4} = s^{-1}$ = s Since s is raised to the -1 it goes on top and becomes s.

$t / t^{2} = 1/t$

Now we combine everything back together:

$\frac{s}{2t}$

8 0

2 years ago

How to find volume of a prism

docker41 [41]

Answer:

- HOW TO FIND VOLUME OF PRISM -

1st step - Write the formula for finding the volume of a regular pentagonal prism. The formula is V = [1/2 x 5 x side x apothem] x height of the prism.

2nd step - Find the area of the pentagonal base face. Let's say the length of a side is 6 cm and the length of the apothem is 7 cm.

3rd step - Find the height. Let's say the height of the shape is 10 cm.

4th step - Multiply the area of the pentagonal base face times the height. ...

and last step - State your answer in cubic units.

Step-by-step explanation:

:):):)

5 0

1 year ago