Answer:
7 units
Step-by-step explanation:
Given is a 45°-45°-90° triangle.
Measure of Hypotenuse = 7 StartRoot 2 EndRoot units.
In a 45°-45°-90° triangle, measures of perpendicular legs is one upon square root 2 times of the measure of Hypotenuse.
![\therefore \: measure \: of \: one \: leg \\ \\ = \frac{1}{ \sqrt{2} } \times 7 \sqrt{2} \\ \\ = 7 \: units](https://tex.z-dn.net/?f=%20%5Ctherefore%20%5C%3A%20measure%20%5C%3A%20of%20%5C%3A%20one%20%5C%3A%20leg%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%5Ctimes%207%20%5Csqrt%7B2%7D%20%20%20%5C%5C%20%20%5C%5C%20%20%3D%207%20%5C%3A%20units)
Answer:
B -9(9x-3)
Step-by-step explanation:
b/c -9(9x-3) means -9×9x-(-3)
= -81x+27
if you say why -(-3) is +27, I will say b/c negative times negetive it give us positive. and if you they why we don't add -81x and 27, I will say b/c they are not like terms.
like terms : are terms with the same variable and same exponent.
example:2x and 3x,5xy and 9yx and etc....
if it helpful ❤❤
THANK YOU
Answer:
okay
Step-by-step explanation:
what questions I want to see if I could answer them
If you carefully match each shape to it's sides, Net A is the correct one. The key is the 14 and 13 sides. The 14 should be vertical in the net.
Surface area is just the area of each individual shape together.
There are the following shapes and dimensions:
Rectangle: 5 x 14 = 70
Rectangle: 12 x 14 = 168
Rectangle: 13 x 14 = 182
2 Triangles: 1/2 x 5 x 12 = 30 x 2 = 60
70 + 168 + 182 + 60 = 480 square inches.
In order to find the inverse of
![A(x)=x^{\frac{1}{5}}+5](https://tex.z-dn.net/?f=A%28x%29%3Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%2B5)
we first replace A(x) with y:
![y=x^{\frac{1}{5}}+5](https://tex.z-dn.net/?f=y%3Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%2B5)
Then we replace every y with an x and every x with a y, like so:
![x=y^{\frac{1}{5}}+5](https://tex.z-dn.net/?f=x%3Dy%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%2B5)
We solve this new equation for y:
![x-5=y^{\frac{1}{5}}\Rightarrow y^{\frac{1}{5}}=x-5](https://tex.z-dn.net/?f=x-5%3Dy%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%5CRightarrow%20y%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%3Dx-5)
We raise both sides of the equation to the fifth power:
![(y^{\frac{1}{5}})^5=(x-5)^5](https://tex.z-dn.net/?f=%28y%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E5%3D%28x-5%29%5E5)
![y=(x-5)^5](https://tex.z-dn.net/?f=y%3D%28x-5%29%5E5)
Finally, we replace y with the inverse of the function:
![A^{-1}(x)=(x-5)^5](https://tex.z-dn.net/?f=A%5E%7B-1%7D%28x%29%3D%28x-5%29%5E5)
and that is the inverse function.