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marusya05 [52]
3 years ago
13

The rectangle has a length of (x+3) and the width (x+1)

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0
The answer is b
Because you have to add da x and dat is 2x den add da numbers which is 4
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Round 3.251 to the hundredths place.
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It would be 3.25 because you can’t round 0.001 up
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Which of the following is not a way to represent the solution of the inequality 2(x − 2) less than or equal to 2?
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The answer is A  A number line with a closed circle on 3-
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Can someone please help me!
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I think it should be 90° since x is a right angle
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The ordered pair (4, -8) is in the 4th quadrant if we took the opposite of the x- value and the opposite of the y-value, which q
harina [27]

9514 1404 393

Answer:

  2nd quadrant

Step-by-step explanation:

Reversing the signs of both coordinates reflects the point across the origin. The quadrant diagonally opposite quadrant 4 is quadrant 2.

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You recall that quadrants are numbered 1 to 4 counterclockwise, starting from upper right.

8 0
3 years ago
A person in a casino decides to play 3 games of blackjack. let w denote a win and l denote a loss. define the event a as "the pe
Ann [662]

Answer: The answer is {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.



Step-by-step explanation: Given that a person in the casino is going to play 3 games of blackjack. Here, 'w' denotes a win and 'l' denotes a loss.  

Also, let 'A' be the event that the person wins at least one game of blackjack. Then, the outcomes of Event 'A' are

(i) win in 1st game     loss in 2nd game       loss in 3rd game

(ii) win in 1st game     win in 2nd game        loss in 3rd game

(iii) win in 1st game     loss in 2nd game       win in 3rd game

(iv) win in 1st game     win in 2nd game        win in 3rd game

(v) loss in 1st game     loss in 2nd game       win in 3rd game

(vi) loss in 1st game     win in 2nd game        loss in 3rd game

(vii) loss in 1st game     win in 2nd game       win in 3rd game

Thus, the outcomes of the event A are (w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l) and (l, w, w).

Thus, A = {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.


5 0
3 years ago
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