Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Answer:
It's a.
Step-by-step explanation:
(a - 2b)^2 + 8ab
= a^2 - 4ab + 4b^2 + 8ab
= a^2 + 4ab + 4b^2.
((a + 2b)^2 = a^2 + 4ab + 4b^2.
The scale factor equal to 1 will have No Effect on the dimensions of the image being scaled .
In the question ,
it is given that ,
the scale factor is = 1.
we have to find the effect of change ;
we know that ,
when the value scale factor is greater than 1 , then dimensions of new image is larger than original .
when the value of scale factor is 1 , then there is no change in the dimensions of the image .
when the value of scale factor is less than 1 , then the dimensions of new image is smaller than the original .
Therefore , if the scale factor is 1 , then there is no change in the dimensions of the image .
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Answer:
C. m+n/2
Step-by-step explanation:
Factor out the 3 in the numerator and apply the difference of squares, factor out the 6 in the denominator, and reduce where applicable. It'll all cone out to look like option C.
I'm not good at math i cant help
