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VMariaS [17]
4 years ago
7

Can some please help me with Algebra 2 work? Its problems 45-48 all and 53-57 just odd numbers

Mathematics
1 answer:
Elanso [62]4 years ago
8 0

45)

E = mc²     <em> (solve for "m" by dividing both sides by c²)</em>

E/c² = m

46)

c(a + b) - d = f  <em>(to solve for "a"; add "d", divide by "c" and then subtract "b")</em>

c(a + b)     = f + d

(a + b)       = (f + d)/c

a              = (f + d)/c  - b

47)

z = πq³h  <em> (solve for "h" by dividing both sides by πq³)</em>

z/πq³ = h

48)

(x + y)/z - a = b   <em> (solve for "y"; add "a", multiply by "z", and then subtract "x")</em>

(x + y)/z      = b + a

(x + y)         = z(b + a)

     y           = z(b + a) - x

53)

5x - 9 = 11x + 3

     -9 = 6x + 3      <em>subtracted 5x from both sides</em>

    -12 = 6x          <em>subtracted 3 from both sides</em>

      -2 = x           <em>divided both sides by 6</em>

55)

5.4(3k - 12)   +   3.2(2k + 6) = -136

16.2k - 64.8   +  6.4k + 19.2 = -136      <em>distributed 5.4 and 3.2</em>

22.6k - 45.6 = -136             <em>added like terms (16.2k + 6.4k and -64.8 + 19.2</em>

22.6k = -90.4                    <em>added 45.6 to both sides</em>

      k = -4                       <em>divided both sides by 22.6</em>

57)

(4/9)y + 5 = (-7/9)y - 8

4y + 45 = -7y - 72           <em>multiplied by 9 to clear the denominator</em>

11y + 45 = -72                 <em>added 7y to both sides</em>

11y         = -99                  <em>subtracted 45 from both sides</em>

y            = -9                    <em>divided both sides by 11</em>



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5f

Step-by-step explanation:

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3 years ago
The sum of the diagonals of a rhombus is 5√2.
Alex
Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC
= \frac{1}{2} BD (AO + OC)
\frac{1}{2} BD \times AC

So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}
BD \times AC = 8
Now, AC + \: BD = 5 \sqrt{2}

Squaring both sides, we get
AC {}^{2} + BD {}^{2} + 2 AC.BD =50
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AC {}^{2} + BD {}^{2} = 50 - 16
AC {}^{2} + BD {}^{2} = 34

In △AOB, we have
OA {}^{2} + OB {}^{2} =AB {}^{2}
( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}
\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}
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Square rooting both sides
\sqrt{34} = 2 AB
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Hope it helps!

7 0
4 years ago
(3+5^2)(5-4^2) how to simplify?​
sveta [45]

Answer:

-308

Step-by-step explanation:

(3+5^2)(5-4^2)

28(5-4^2)

28(-11)\\

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Hope that helped!

3 0
3 years ago
Two angles are complementary. The larger
tensa zangetsu [6.8K]

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Step-by-step explanation:

4 0
3 years ago
PLEASE HELP :) I will give all points
yan [13]

answer choice a

x^2 - 5x - 1 = 0

a=1, b=-5, and c=-1

next you plug in the numbers into the quadratic formula

-(-5) plus or minus the square root of (-5)^2 - 4(1)(-1)/ 2(1)

after you simply, you should get 5 plus or minus the square root of 29, which is answer choice a

8 0
4 years ago
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