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andreev551 [17]
3 years ago
13

Serena is hitting golf balls at the driving range. When she hit a ball with her 9-iron, it stopped x yards in front of the 100-y

ard marker. She knows she can hit a ball twice that far if she uses her driver. Complete the steps below to see how far Serena can hit a golf ball with her driver.
Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

the golf ball stopped x yards in front of the 100-yard marker. So, the expression 100-x represents the distance Serena hit the ball with her 9-iron.

Step-by-step explanation:

ch4aika [34]3 years ago
5 0

Answer:

100-x represents the distance that Serena hit with her 9-iron. 2(100-x) represents the distance she can hit using her driver.

When the distance is given for the 9-iron, use the distributive property to find the simplified equation, so it will be much easier to solve after you are given the information on the 9-iron. Unsolvable without 9-iron distance.

Step-by-step explanation:

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It's simple.
First multiply 3 by 4
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Can Someone Help Me With a Few Math Questions?
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7 0
3 years ago
1)the mean of a, b, c, d, and e is 86. The mean of a, b, and c is 80 What is the mean of d and e?
Paraphin [41]
Since a,b and c is 80 then d and e is 6
8 0
3 years ago
If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun
saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ]  are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

P(t)=181843(1.04)^{(\frac{t}{10})}

where, P(t) is population after t years.

At t=5,

P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20

At t=6,

P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95

At t=7,

P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57

At t=8,

P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06

At t=9,

P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44

At t=10,

P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72

The rate of change of P(t) on the interval [x_1,x_2] is

m=\frac{P(x_2)-P(x_1)}{x_2-x_1}

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504

The average rate of change of the population on the intervals [ 5 , 9 ] is

m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06

The average rate of change of the population on the intervals [ 5 , 8 ] is

m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62

The average rate of change of the population on the intervals [ 5 , 7 ] is

m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185

The average rate of change of the population on the intervals [ 5 , 6 ] is

m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ]  are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0
4 years ago
A movie club charges a one-time
Mama L [17]

Answer:

Step-by-step explanation:

Club A charges $30 membership fee and charges $7 for each movie.

You can write this as :

A = 30 + 7m  (where m = number of movies)

Club B charges no membership fee and it costs $12 for each movie.

B = 12m

If we want to find how many movies a member must purchase for the total cost of the two clubs to be the same, this means we are trying to solve for "m" (number of movies) when A = B.

30 + 7m = 12m

Now you can just subtract 7m from both sides.

30 = 5m

Divide both sides by 5 to find "m'.

m = 30/5 = 6

Therefore a member must purchase 6 movies

6 0
3 years ago
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