You have to find two definite points on the graph, i'll use (1,4) and (2,6) as an example
The slope formula is (y2-y1)/(x2-x1)
This means you have to subtract the first y value from the second divide it by the first x value subtracted from the second
In my example you have to do (6-4)/(2-1) to get 2/1, or 2
Hope this helps!
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
6x/6y=6z
X/?Y=1/2Z
36=6
1hole take 1 man x 6 days
1/2 hole needs 1 man with 3 days
3785.41 milliliters per gallon
